Matching Lace Bind Off
So here’s an example of the decorative lace cast on that I’m considering using for the River shawl.
I like the nice loops, but now I can’t figure out what a good matching bind off would be. The trick here is that there are half as many of these loops as the number of stitches you cast on. So I can’t figure out how to duplicate this when binding off. Here’s a yarn over bind off.
The yarn overs kind of duplicate the decorative loops in the cast on, but there are those connecting smaller loops between the yarn over loops that makes the bind off look different.
What to do? Maybe I’ll just go with a very loose cast on and bind off and just get started. But on what needles…?
I can’t seem to find just the right needles for the project. Nothing seems to be pointy AND slippery AND long enough for me. And there are no 7 mm US equivalent needles around. But wait, I just noticed my Denise needles. They’re pointy and slippery and long enough. But I’m not sure if the join between the cord and needle will be smooth enough. And of course there is no 7 mm size, but I already gave up on finding that. I did just finish a fuzzy shawl with lots of YO and K2Tog. I’m quite used to the Denise needles now. Maybe I’ll go with them.
Comments
3 Comments on Matching Lace Bind Off
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Grin and Frog It » Finished Project: River Shawl on
Mon, 19th Jun 2006 9:02 am
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Grin and Frog It » Another River Shawl on
Wed, 6th Sep 2006 10:21 am
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Jennifer on
Thu, 11th Dec 2008 12:58 pm
[...] nd with only one row of yarn overs. My Blog Links: Upcoming Projects, Cast On Lace Method, Matching Lace Bind Off, Emerging Pattern, New Summer Project, Tedious Beads, Finishing Up Projects, River [...]
[...] the store and in the black Kidsilk Night. And this time I’ll be able to use my much pointier Knitpicks needles. I’ll cast on as soon as I finish a little dinosaur I’m making. [...]
Beautiful work! You look stunning in that outfit. I’m about to begin a lace project myself. Have you found the ultimate cast on/bind off? I saw your post about casting on and I think it will work, but have you come across any other methods?
